5x^2-7x+20=0

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Solution for 5x^2-7x+20=0 equation:


Simplifying
5x2 + -7x + 20 = 0

Reorder the terms:
20 + -7x + 5x2 = 0

Solving
20 + -7x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
4 + -1.4x + x2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -1.4x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + -1.4x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1.4x + x2 = 0 + -4
-1.4x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
-1.4x + x2 = -4

The x term is -1.4x.  Take half its coefficient (-0.7).
Square it (0.49) and add it to both sides.

Add '0.49' to each side of the equation.
-1.4x + 0.49 + x2 = -4 + 0.49

Reorder the terms:
0.49 + -1.4x + x2 = -4 + 0.49

Combine like terms: -4 + 0.49 = -3.51
0.49 + -1.4x + x2 = -3.51

Factor a perfect square on the left side:
(x + -0.7)(x + -0.7) = -3.51

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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